Solve the system 2x-3y=12 and x+5y=14.

Given the equations:

2x-3y =
12 .............(1)

x+5y =
14.................(2)

We need to solve for x and
y.

We will use the substitution method to
solve.

From (2) we will rewrite x=
14-5y

Now we will substitute into
(1).

==> 2x-3y =
12

==> 2(14-5y) - 3y =
12

==> 28 - 10y - 3y =
12

==> -13y =
-16

==> y=
16/13

==> x= 14-5y = 14- 5*16/13 =
102/13

==> x=
102/13

Then the answer is: x= 102/13  and y=
16/13