Given the equation.
x^2 + kx
-6 = (x-2)(x+3)
We need to find the values of
k.
First we will simplify the right side by opening the
brackets.
==> x^2 + kx -6 = x^2 +3x -2x -
6
==> x^2 + kx -6 = x^2 + x -
6
Now we will add 6 to both
sides.
==> x^2 + kx = x^2 +
x
Now we will subtract x^2 from both
sides.
==> kx = x
Now
we will divide by x .
==> k = x/x =
1
==> Then the values of k =
1.
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