What is x if 2^(3x-1) = 16.

Given the exponent equation 2^(3x-1) =
16.

We need to find the values of x that satisfies the
equation.

First we will simplify the right
side.

We know that 16 = 4*4 = 2*2*2*2 =
2^4

Then we will rewrite into the
equation.

==> 2^(3x-1) =
2^4

Now that the bases are equal, then the powers should be
equal too.

==> 3x-1 =
4

We will solve by adding 1 to both
sides.

==> 3x = 5

Now
we will divide by 3.

==> x =
5/3.