The sum of three consecutive even integers is equal to 84. Find the numbers

Let the first even integer be x, Then the next even
integer is (x+2) and the third is (n+4).

Given that the sum
of the three even integers is 84.

Then we will rewrite into
an equation as follow:

n + (n+2) + (n+4) =
84

Now we will combine like
terms.

==> 3n + 6=
84

Now we will subtract 6 from both
sides.

==> 3n = 78

Now
we will divide by 3.

==> n=
26

==> n+2 =
28

==> n+4 =
30

Then, the three consecutive even integers
are 26, 28, and 30.