Find the intercepts of the line L given by (-1/2)y - 12 = x

Given the line (-1/2)y -12 =
x

We need to find the intercepts ( x-intercept and
y-intercept).

Let us determine the
y-intercept.

The y-intercept is the point where the line
intersects with the y-axis.

Then the values of x will be
zero.

==> (-1/2)y -12 =
0

==> -1/2 y=
12

==> -y =
24

==> y= -24

Then the
y-intercept is the point (0, -24).

Now we will determine
the x-intercept.

The x-intercept is the point where the
line meets the x-axis.

Then the value of y is
0.

==> (-1/2)*0 - 12 =
x

==> x =
-12

==> x-intercept is the point ( -12,
0)

Then the intercepts are : (x-intercept is
( -12,0) and y-intercept is ( 0, -24)