What is the solution to: 1/16 = 64^(4x+7)I think you have to use natural log or log, but i'm not sure which.

We notice that we can create matching bases both sides.
We'll write  and 64 as powers of 2.

1/2^4 =
(2^6)^(4x+7)

For the term from the left side, we'll apply
the negative power rule:

1/2^4 =
2^-4

By definition, we'll multiply the exponents of the
term from the right side:

2^-4 = 2^(24x +
42)

Since the bases are matching now, we can apply the one
to one property of exponentials.

-4 = 24x +
42

We'll re-write the
equation:

24x + 42 = -4

We'll
isolate x to the left side:

24x = -4 -
42

24x = -46

We'll divide by
24:

x = -46/24

x =
-23/12

The solution of the equation is x =
-23/12.