solve the equation 3x^2 +8x -13 = 0

Given the quadratic equation: 3x^2 + 8x -13 =
0

We need to find the roots of the equation
.

We will use the formula to find the
answer.

We know that a= 3   b= 8  and c=
-13

==> x= [ -b +-
sqrt(b^2-4ac)]/2a

==> x1= [ -8 + sqrt(64-4*3*-13) ]/
2*3

            = [ -8 + sqrt(220)]/
6

           = ( -8 +
2sqrt55]/6

              =
(-4+sqrt55)/3

==> x2= (
-4-sqrt55)/3

Then the roots for the quadratic equation
is:

x= { (-4+sqrt55)/3  . (-4-sqrt55)/3 
}