Given that 0, -2, and 3 are the zeros of the function
f(x).
Then x, (x+2), and (x-3) are the factors of
f(x).
Then f(x) =
x(x-3)(x+2).
Now we need to find the solutions for
f(x-2)
Then, we will substitute with (x-2) in place of x
into the equation.
==> f(x-2) = (x-2) ( x-2 -3)
(x-2+2)
==> f(x-2) =
(x-2)(x-5)(x)
Then the zeros of f(x-2) are 2, 5, and
0
Then the solution for f(x-2) are 0, 2, and
5.
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