Assume that a wheel has an outside diameter of 0.800 km and an inside diameter of 0.720 m.Use mathematical calculations to show how a simulated...

I'm assuming your wheel has an inside diameter of 0.720
kilometers, not meters, since the outside diameter is in kilometers.....The
gravitational force on Earth is 9.8 meters per second squared, or 9.8 m/sec^2.  That
force can be induced upon your wheel if its spinning at a specific rate.  The
relationship between the gravitational force (or acceleration), the angular velocity of
the wheel, and the radius is given by the formula

a =
W^2r

where a is acceleration in m/sec^2, W is the angular
velocity in radians per second (a radian is a measure where the radius length equals an
arc length of a circle) and r is the radius.  In this
case,

9.8 m/sec^2 = W^2 (800
m)

.01225 m^2/sec^2 =
W^2

.1106 m/sec = W

so your
wheel would have to be spinning at about a tenth of a meter per second for a radius of
800 m.

See the link for an actual gravitational
calculator: