What are the dimensions of the rectangle if the perimeter is 27 and the length is two times the width.

Let the length of the rectangle be L and the width be
W.

Given that the perimeter is
27.

==> P = 2L + 2W =
27

We will divide by
2.

==> L + W = 27/2
................(1)

Also, given that the length is two
times the width.

==> L = 2*W
.............(2)

We will substitute (2) into
(1).

==> 2W + W =
27/2

==> 3W = 27/2

Now
we will divide by 3:

==> w = 27/2*3 = 9/2 =
4.5

==> L = 2* 4.5 =
9

Then the dimensions of the rectangle are 9
and 4.5.