solve 3sec^2x = 5 for 0

We have to solve 3*(sec x)^2 = 5 for x between 0 <
x < 2*pi

3*(sec x)^2 =
5

3*(1/ cos x)^2 = 5

=>
(cos x)^2 = 3/5

cos x =  sqrt (3/5) and cos x = -sqrt
(3/5)

x = arc cos
(sqrt(3/5))

x = 39.23 degrees and 320.768
degrees.

cos x =
-sqrt(3/5)

=> x = arc cos(- sqrt
(3/5))

x = 140.76 and x =
219.23

The required values of x are {39.23,
140.76, 219.23, 320.768}