In other words, we'll have to calculate the indefinite
integral of y.
Int [e^(13x)+sin x]dx/10 =
(1/10)*[Inte^(13x)dx + Int sin x dx ]
We'll calculate each
term of the sum:
Inte^(13x)dx = e^(13x)/13 +
c
Int sin x dx = -cos x +
c
We'll substitute the integrals by their results and we'll
get:
Int [e^(13x)+sin x]dx/10 = [e^(13x)]/130
- (cos x)/10 + c
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