Thursday, September 26, 2013

What is the square root of (-7 + 24i)?

Let the required square root of -7 + 24i be x +
yi


x + yi = sqrt ( -7 +
24i)


square both the sides


x^2
- y^2 + 2xyi = -7 + 24i


equate the real and complex
coefficients


x^2 - y^2 =
-7


2xy = 24


=> xy =
12


=> x =
12/y


Substitute in x^2 - y^2 =
-7


=> 12^2/y^2 - y^2 =
-7


=> 144 - y^4 + 7y^2 =
0


=> y^4 - 7y^2 - 144 =
0


let u = y^2


=> u^2 -
7u - 144 = 0


=> u^2 - 16u + 9u - 144 =
0


=> u(u - 16) + 9(u - 16) =
0


=> (u - 16)(u + 9) =
0


=> u = 16 and u =
-9


y = sqrt u is a real number so we take only u =
16.


y^2 = 16 , y = 4 and y =
-4


x = 12/y = 3 and
-3


The required value of sqrt( - 7 + 24i) =
-3 - 4i and 3 + 4i

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