Given the equation:
3x^2 + 5x
-12 = 0
We need to solve for
x.
We will use the formula to find the roots of the
quadratic equations.
We know
that:
x = [ -b +- sqrt(b^2-4ac)/
2a
==> x1= ( -5 +
sqrt(25-4*3*-12)]/2*3
= (-5 + sqrt(169) /
6
= (-5 +13)/6 = 8/6 =
4/3
==> x1=
4/3
==> x2= (-5 -13)/6 = -18/6 =
-3
==> x2= -3
Then the
solution for the quadratic equation is:
x= {
4/3 , -3}
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