Calculate the expression sin^-1(sin(5pi/3))+tan^-1(tan(2pi/3))?

We'll solve the problem based on the following
rules:

sin^-1(sin(x)) = arcsin (sin x) = x and arctan(tan
x) = x

tan^-1(tan(x)) = arctan(tan x) =
x

According to these rules, we'll
get:

arcsin (sin (5pi/3)) =
5pi/3

arctan(tan (2pi/3)) =
2pi/3

arcsin (sin (5pi/3)) + arctan(tan (2pi/3)) = 5pi/3 +
2pi/3

arcsin (sin (5pi/3)) + arctan(tan (2pi/3)) =
7pi/3

The values of the given sum of inverse
trigonometric functions is 7pi/3.