Given the quadratic
equation:
6x^2 + 5x -3 =
0
Then we know that a = 6 b= 5 and c =
-3
We will use the quadratic formula to find the
roots.
We know that:
x = [ -b
+- sqrt(b^2-4ac)] / 2a
==> x1 = [ -5 +
sqrt(25+4*6*3)]/ 2*6
= ( -5 + sqrt97) /
12
==> x2= (
-5-sqrt97)/12
Then the roots
are:
x = { (-5+sqrt97)/12 , (-5-sqrt97)/12
}
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