Given that the second term is 5 and the 6th term is 17 in
an A.P.
Let the common difference be r and the first term
is a1.
Then we know that:
a2=
a1+ r
==> 5 = a1+
r...............(1)
Also we know
that:
a6 = a1+ 5r
==>
17 = a1+ 5r ..............(2)
Now we will solve the system
.
We will subtract (1) from
(2).
==> 12 =
4r
==> r= 3
Now we will
substitute into (1) to find a1.
==> 5= a1+
r
==> 5= a1+ 3 ==> a1= 5-3 =
2
Then the first term is a1=2 and the common
difference is r=3
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