Find dy/dx for y = ( 4x - 1)(sin3x)Step by step process

We have to find the derivative of y = ( 4x -
1)(sin3x)

y = ( 4x -
1)(sin3x)

=> y = 4x* sin 3x - sin
3x

Now use the product rules and the chain
rule

dy/dx = [4x* sin 3x]' - [sin
3x]'

=> [4x]'* sin 3x + 4x*(sin 3x)' - [sin
3x]'

=> 4*sin 3x + 4x*3*cos 3x - 3*cos
3x

=> 4*sin 3x + 3*cos 3x*(4x -
1)

The required derivative is 4*sin 3x +
3*cos 3x*(4x - 1)