The total cost is given by TC = 3x^2 + 3xy + 2y^2 -
100.
The total revenue is: TR = 54x +
52y
The profits made are P = TR - TC = 54x + 52y - 3x^2 -
3xy - 2y^2 + 100.
As x + y = 10, we can replace y with 10 -
x. This gives:
P = 54x + 52(10 - x) - 3x^2 - 3x(10 - x) -
2(10 - x)^2 + 100
=> 54x + 520 - 52x - 3x^2 - 30x +
3x^2 - 200 - 2x^2 + 40x + 100
=> P = 12x - 2x^2 +
420
To maximize we solve dP/dx =
0
=> -4x + 12 =
0
=> x = 12/4 = 3
y =
10 - x = 7
To maximize profits 3 of x and 7
of y should be produced.
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