Let one of the numbers be x and the other is
y.
Given that the sum of the numbers is
12.
==> x + y=
12............(1)
Also, given that the product is
27.
==> x*y =
27...............(2)
Then we have a system of two equations
ans two variables.
We will use the substitution method to
solve.
From (1) we know that x=
12-y
==> x*y =
27
==> (12-y)*y =
27
==> 12y - y^2 =
27
==> y^2 - 12y + 27 =
0
Now we will
factor.
==> (y-9)(y-3) =
0
==> y1- 9 ==> x1= 12-9 =
3
==> y2= 3 ==> x2 =12-3 =
9
Then the numbers are 3 and
9.
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