Find the slope of the line that is perpendicular to the line that passes through the points (1,3) and (2,6)?

We know that 2 line are perpendicular if and only if the
product of the values of their slopes is -1.

We can find
the slope of the line that passes through the given
points.

m1 = (y2 - y1)/(x2 -
x1)

m1 = (6-3)/(2-1)

m1 =
3/1

m1 = 3

The product of the
slopes is:

m1*m2 = -1

-3*m2 =
-1

We'll divide by -3:

m2 =
1/3

The slope of the perpendicular line to
the line that passes through the points (1,3) and (2,6) is m2 =
1/3.