what is x,y from the equation.3x-ix-2y=12-iy-iPlease help

We need to find x and y from 3x - ix - 2y = 12 - iy -
i

3x - ix - 2y = 12 - iy -
i

=> 3x - 2y - ix = 12 - i(y +
1)

equate the real and the complex
coefficients.

3x - 2y = 12

x =
y + 1

substitute in 3x - 2y =
12

=> 3(y + 1) - 2y =
12

=> 3y + 3 - 2y =
12

=> y = 9

x  = y +
1

=> x =
10

The required values are x = 10 and y =
9.