Find three consecutive integers whose sum is equal to 366

Let us assume that the first integer is n. Then the next
integer is (n+1) and the third integer is (n+2)

Given that
the sum of the three integers is 366

Then we will write as
algabraic expression.

==> n + (n+1) + (n+2) =
366

Now we will combine like
terms.

==> 3n + 3 =
366

Now we will subtract 3 from both
sides.

==> 3n = 363

Now
we will divide by 3.

==> n =
121

==> n+1 =
122

==> n+2 =
123

Then, the three consecutive integers are
121, 122, and 123.