We have the function f(x) = x/(x - 1)^2 and we have to
find the first and the second derivatives.
f(x) = x/(x -
1)^2
=> f(x) = x*(x -
1)^-2
Use the product rule to calculate the first
derivative
f'(x) = x*(-2)(x - 1)^(-3) + (x -
1)^(-2)
=> -2x*(x - 1)^(-3) + (x -
1)^(-2)
=> -2x/(x - 1)^3 + 1/(x -
1)^2
Again use the product rule to calculate the second
derivative
f'(x) = -2x*(x - 1)^(-3) + (x -
1)^(-2)
f''(x) = (-2)[(x - 1)^(-3) + (-3)*x*(x - 1)^(-4) +
(-2)*(x - 1)^(-3)
=> -2/(x - 1)^3 + 6x/(x - 1)^4 -
2/(x - 1)^3
=> -4/(x - 1)^3 + 6x/(x -
1)^4
The first derivative is -2x/(x - 1)^3 +
1/(x - 1)^2 and the second derivative is -4/(x - 1)^3 + 6x/(x -
1)^4
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