To calculate the area of the region bounded by the graph
of the function f, x axis and the given lines x=1 and x=e, we must to evaluate the
definite integral of the function f(x) = (x-1)/x^2
Int
f(x)dx=Int [(x-1)/x^2]dx
We'll aply the property of
integrals to be additive:
Int (x/x^2)dx - Int
(1/x^2)dx=
Int (1/x)dx - Int [x^(-2)]dx = ln x -
[x^(-2+1)]/(-2+1)
We'll apply Leibniz-Newton
formula:
Int f(x)dx= F(e) -
F(1)
F(e) - F(1) = (ln e - ln 1) + (1/e -
1)=
=
1-0+(1/e)-1=1/e
The value of the area of the
region bounded by the graph of the function f, x axis and the given lines x=1 and x=e is
A = 1/e square units.
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