What is x if log(x) (1/8) = -3/2.

Given that log(x) (1/8) =
-3/2

We need to find the values of
x.

==> Let us
simplify.

First we will rewrite (1/8) =
(1/2)^3

==> (1/2)^3 =
2^-3

==> log(x) 2^-3 =
-3/2

Now we know that log a^b = b*log
a

==> log(x) 2^-3 = -3*log(x) 2 =
-3/2

We will divide by
-3.

==> log(x) 2 = -3/2*-3 =
1/2

Now we will rewrite using exponent
form.

==> x^1/2 = 2

We
will square both sides.

==> x =
4