How to solve the equation `sqrt(3)sin x-cosx=0` ?

The question is not very clear, i.e is it sqrt(3)
sinx-cosx =0 or sqrt(3sinx)-cos x=0

I will do it for the
questions:

1) sqrt(3) sinx - cos x
=0

or sqrt (3) sinx = cos
x 

or, sinx/cosx = tanx =
1/sqrt(3) 

i.e. x = pi/6 (or 30
degrees)

2) sqrt (3 sinx)-cosx=
0

or 3sinx = cos^2 x = 1- sin^2
x

(using sin^2 x + cos^2 x =
1)

or, sin^2x + 3 sinx -1 =
0

solving this quadratic equation, we get sin x = (1/2) x
(-3+ sqrt (13))

or, x = 17.62
degrees.