When x=3 and y=5 how much does 3x^2-2y exceed the value of 2x^2 - 3y?

Given that x= 3 and y=
5

First we will find the value for each expression then
compare the results.

The first expression is 3x^2 -
2y

We will substitute with x- 3 and y-
5

==> 3*3^2 - 2*5 = 27 - 10 =
17..........(1)

Now we will calculate the second expression
2x^2 - 3y

==> 2*3^2 - 3*5 = 18 - 15 =
3................(2)

Now the difference between the values
is 17-3 = 14.

Then we conclude that the value
of 3x^2 - 2y exceeds the value of 2x^2 - 3y by
14.