How to find the intersection of line y=12x+8 with axis?

We know that when a line is intersecting x axis, the value
of x is the solution of the equation.

We'll have the
equation of the line y = 12x+8 (1).

12x+8 = 0
(2)

x = -8/12

x =
-2/3

Comparing (1) and (2), we'll get y =
0.

So, the line is intercepting x axis in the point (-2/3 ,
0).

We'll conclude that if we want to find out the y
intercepting point, we'll have to put x = 0.

y =
12x+8

For x = 0 => y = 12*0 +
8

y =
8

Therefore, the line is intercepting x axis
in the point (-2/3 , 0) and the line is intercepting y axis in the point (0 ,
8).