We'll have to use the chain rule since the given
function is the result of composition of 2 functions.
u(x)
= x^5+6x and v(u) = u^7
y = f(x) = (vou)(x) = v(u(x)) =
v(x^5+6x) = (x^5+6x)^7
We'll differentiate f(x) and we'll
get:
f'(x) =
v'(u(x))*u'(x)
First, we'll differentiate v with respect to
u:
v'(u) = 7u^(7-1) =
7u^6
Second, we'll differentiate u with respect to
x:
u'(x) = (x^5+6x)' = 5x^4 +
6
f'(x) = 7u^6*(5x^4 +
6)
We'll substitute u and we'll get the derivative of f(x)
= y.
The derivative of f(x) is: f'(x) =
7*(5x^4 + 6)*(x^5+6x)^6.
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