Find the derivative of g(x) = 2x^3+5x^2 -3x + 7

We have the function g(x) = 2x^3 + 5x^2 - 3x +
7.

We need to find the first derivative of
g(x).

By definition we know that the derivative of ax^b =
a*b*x^(b-1).

Then, we will apply the rule to all
terms.

==> g'(x) = (2x^3)' + (5x^2)' -(3x)' + (7)
'

==> g'(x) = 6x^2 + 10x - 3 +
0

Then, the first derivative is g'(x) and given
by:

==> g'(x) = 6x^2 + 10x -3