Solve algebraically for x: (x + 2)/6 = 3/(x - 1)

To solve x + 2/ 6 = 3/ x -
1

We assume both sides are monomials like (x+2)/6 = 3/(x-1)
and not
binomials.

Now we
multiply both sides by 6(x-1) and get:

(x-1)(x+2) =
3*6

x^2+x-2 = 18

x^2+x-2-18 =
18-18

x^2+x-20 = (x+5)(x-4) =
0

Therefore either of the factors x+5 = 0 or x-4 =
0.

This gives x = -5 or x=
4.