What is the solution for 3x^2 + 6x

We have to find the solutions of 3x^2 + 6x <
9

3x^2 + 6x <
9

=> 3x^2 + 6x - 9 <
0

=> x^2 + 2x - 3 <
0

=> x^2 + 3x - x - 3
<0

=> x(x + 3) -1 (x + 3) <
0

=> (x - 1)(x + 3) <
0

For (x - 1)(x + 3) to be less than 0 , either of them
should be less than 0

=> x - 1 < 0 and x + 3
> 0

=> x < 1 and x >
-3

This gives a set of values as (-3 ,
1)

x - 1 > 0 and x + 3 <
0

=> x > 1 and x < -3 gives no
solutions.

As x is an integer (-3 , 1) implies (-2 , -1 ,
0)

So x can have the values (-2 , -1 ,
0).