Given that sin(t) = 5/7, we need to find cos(x) and
tan(x)
We will use trigonometric identities to find
cos(x)
We know that sin^2 x + cos^2 x =
1
==> cosx = +-sqrt(1-sin^2
x)
Let us substitute with sinx =
5/7
==> cosx = +-sqrt(1-
(5/7)^2]
= +-
sqrt(1-25/49)
=
+-sqrt(24/49)
= +-2sqrt6/
7
Then cosx = +- 2sqrt6 /
7
Now we know that tanx =
sinx/cosx
==> tanx = (5/7) / (+-2sqrt6 /
7)
= +-
5/2sqrt6
= +-5sqrt6/
12
==> tanx= +-5sqrt6 /
12
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