If f(x)=4x , g(x)=2x-1 and h(x)=x^2+1, what is fogoh(x)? Please simplify the result.

The functions f(x)=4x , g(x)=2x-1 and h(x)=x^2+1. We need
to determine fogoh(x)

fogoh(x) =
f(g(h(x)))

=> f(g(x^2 +
1)

=> f( 2*(x^2 + 1) -
1)

=> 4*(2*(x^2 + 1) -
1)

=> 4*(2x^2 + 2 -
1)

=> 4*(2x^2 +
1)

=> 8x^2 +
4

The required value of fogoh(x) = 8x^2 +
4