Multiply (x*y^2*z^3-v^4)(x*y^2*z^3+v^4) but do not use Foil method.

We'll recognize the form (a-b)(a+b) and the product will
become the difference of 2 squares.

(a-b)(a+b) = a^2 -
b^2

a = x*y^2*z^3 and b =
v^4

We'll raise to square a and
b:

a^2 = (x*y^2*z^3)^2 =
x^2*y^2*z^6

b^2 = (v^4)^2 =
v^8

Therefore, the result of multiplication,
without using FOIL method, is: (x*y^2*z^3-v^4)(x*y^2*z^3+v^4) = x^2*y^4*z^6 -
v^8.