Solve e^(.5ln(.25(x^2 + 4))) = 1

We have to solve e^(0.5*ln(.25(x^2 + 4))) =
1

e^(0.5*ln(0.25(x^2 + 4))) =
1

use the property that a*log b = log
b^a

e^(ln(0.25(x^2 + 4))^(0.5)) =
1

e^ln a = a as ln represents logarithm to the base
e

0.5*(x^2 + 4)^(0.5) =
1

=> sqrt (x^2 + 4) =
2

=> x^2 + 4 =
4

=> x^2  = 0

=>
x = 0

The required solution is x =
0