First, we'll note this expression by
E.
E = arctan
(1/3)+arctan(1/5)+arctan(1/7)+arctan(1/8)
We'll put arctan
(1/3) = a and arctan (1/5) = b.
We'll subtract
arctan(1/7)+arctan(1/8) both sides:
E -
(arctan(1/7)+arctan(1/8)) = a + b
We'll also note
arctan(1/7) = c and arctan(1/8) = d
E - (c+d) = a +
b
We'll apply tangent function both
sides:
tan [E - (c+d)] =
tan(a+b)
We'll recall the
identity:
tan(a+b) = (tan a + tan b)/(1 - tan a*tan
b)
But tan(arctan x) =
x.
Accordingly to this identity, we'll
have:
tan[arctan (1/3)+arctan(1/5)] = (1/3 + 1/5)/(1 -
1/15)
tan[arctan (1/3)+arctan(1/5)] =
8/14
tan[arctan (1/3)+arctan(1/5)] =
4/7
tan [E - (c+d)] = [tan E - tan
(c+d)]/[1-tanE*tan(c+d)]
Tan(c+d) = (1/7 + 1/8)/(1 +
1/56)
Tan(c+d) =
15/55
Tan(c+d) = 3/11
tan [E
- (c+d)] = [tan E - 3/11]/[1-tanE*3/11]
tan [E - (c+d)] =
(11tan E - 3)/(11 + 3tan E)
The expresison will
become:
(11tan E - 3)/(11 + 3tan E) =
4/7
7(11tan E - 3) = 4(11 + 3tan
E)
We'll remove the
brackets:
77tanE - 21 = 44 +
12tanE
We'll move the unknown terms to the
left:
77tanE - 12tanE = 21 +
44
65tanE = 65
We'll divide by
65:
tan E = 1
E =arctan
1
E = pi/4
The
value of the expression E = arctan (1/3)+arctan(1/5)+arctan(1/7)+arctan(1/8) is E =
pi/4.
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