Saturday, June 7, 2014

Determine the equilibrium quantity and equilibrium price and show the points of equilibrium from the following equations. 1. x^2=3y 2. 5x+3y-10=0

You are allowed to ask only one question at a time. I have
deleted your second set of equations and my response is for the first
set.


You have asked for the equilibrium quantity and price
but what the two variables x and y denote is not given.


I
can only determine the value of the two variables using the simultaneous
equations.


x^2 = 3y...(1)


5x +
3y - 10 = 0 ...(2)


Substitute 3y = x^2 in
(2)


=> x^2 + 5x - 10 =
0


x1 = [ -5 + sqrt (25 + 40)]/2 =
1.5311


=> x1 = -5/2 + sqrt 65 / 2 =
-6.5312


x2 = -5/2 - sqrt 65 /
2


y1 = 0.7814


y2 =
14.2185


From the values derived you can determine the price
and quantity that you require, though I do not think it would make any
sense.


The points of equilibrium are ( 1.5311
, 0.7814) and (-6.5312, 14.2185).

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