In other words, we'll have to prove
that:
lim [ln(1+x)]/x =
1
We'll re-write the
function:
lim (1/x)*ln(1+x) =
1
We'll apply the power property of
logarithms:
lim ln [(1+x)^(1/x)] = ln lim
[(1+x)^(1/x)]
But, for x->0 lim [(1+x)^(1/x)] = e
(remarcable limit)
lim ln [(1+x)^(1/x)] = ln
e
We know that ln e =
1
So, for x->0, lim ln [(1+x)^(1/x)]
= 1.
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