Tuesday, February 18, 2014

If the ramp covers 20 feet on the ground, how long is the inclinded surface of the ramp?

INSUFFICIENT DATA PROVIDED- one side does not a triangle
make....


IF- you knew the ANGLE then trigonometry cosine
solution would be valid, however.........


Going back
further to simple algebra/geometry, the question (as stated) still only provides ONE
part of the triangle (ramp viewed from the side).


IF- you
simply knew the HEIGHT of the ramp, then Pythagoras would slip his answer by solving
from square of base (b), square height (a)  get sum and take square
root.


a^2 + b^2 = c^2 -->  
c^(1/2)


>>>>>>EVEN
Betterlook for TRIPLETS!(a TEST time saver!)


IF-  you found
that the height was an equal ratio multiple of 3, then the ramp length would be THAT
equalized multiple of 5   {example: 20 = 5x4, height 15 -->(5x3), then ramp would
be 5x5 = 25!}



YET- Not enough data was given
so....................................


we must walk because
"IF- wishes were horses, then beggars would ride"

No comments:

Post a Comment

Can (sec x - cosec x) / (tan x - cot x) be simplified further?

Given the expression ( sec x - csec x ) / (tan x - cot x) We need to simplify. We will use trigonometric identities ...