Given the equation of absolute
values:
l 2x-3 l = l x-2 l
We
need to find the values of x that verifies the equation.
We
have 4 cases:
case(1):
2x-3 =
x-2
==> x = 1
.......(1)
case(2) :
-(2x-3) =
x-2
-2x +3 = x-2
==>
-3x = -5
==> x= 5/3
.............(2)
Case(2):
-(2x-3)
= -(x-2)
-2x+3 = -x
+2
==> -x =
-1
==> x=
1...............(3)
Case(4)
:
2x-3 = -(x-2)
2x-3 = -x +
2
==> 3x = 5
==>
x= 5/3.............(4)
From the above cases we conclude
that the solution is:
x= { 5/3 ,
1}
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