Find the intersection point of the graph x^2 -3 and the line y= 2x.

At the points where the graphs y = x^2 - 3 and y = 2x
intersect, the x and y coordinates are the same.

Here we
substitute 2x for y in y = x^2 - 3

=> 2x = x^2 -
3

=> x^2 - 2x - 3 =
0

=> x^2 - 3x + x - 3 =
0

=> x(x - 3) + 1( x - 3) =
0

=> (x + 1)(x - 3) =
0

=> x = -1 and x = 3

y
= 2x = -2 and y = 6

The required points of
intersection are (-1, -2) and ( 3, 6)