What is the x intercepts of the curve y=-x^2 + 3x +18 ?.

At the x-intercepts of the curve y = -x^2 + 3x + 18, the
value of y = 0.

So we get 0 = -x^2 + 3x +
18

=> x^2 - 3x - 18 =
0

=> x^2 - 6x + 3x - 18 =
0

=> x(x - 6) + 3(x - 6) =
0

=> (x + 3)(x - 6) =
0

=> x = -3 and x =
6

The required intercepts of y = -x^2 + 3x +
18 with the x-axis are (-3 , 0) and (6, 0)