We recognize a difference of two squares and we'll apply
the formula:
a^2 - b^2 =
(a-b)(a+b)
We'll put a= x^2-4x+4 and b =
x-2
(x^2-4x+4)-(x-2)^2 =
(x^2-4x+4- x+2)( x^2-4x+4+x-2)
We'll combine like terms
inside brackets:
(x^2-4x+4)-(x-2)^2 = (x^2 - 5x +
6)( x^2-3x + 2)
The roots of the first factor, x^2 - 5x +
6, are:
x1 = 2 and x2 = 3
x^2
- 5x + 6 = (x-2)(x-3)
The roots of the second factor,
x^2-3x + 2, are:
x1 = 1 and x2 =
2
x^2-3x + 2 =
(x-1)(x-2)
(x^2-4x+4)^2 - (x-2)^2 =
(x-2)(x-3)(x-1)(x-2)
The final result of the
difference of 2 squares is: (x^2-4x+4)^2 - (x-2)^2 =
(x-3)*(x-1)*(x-2)^2.
No comments:
Post a Comment