The sum of the first and third of three consecutive odd integers is 131 less than three times the second integer. Find the three integers

Let the first even integer be
n.

Then the second even integer be
n+2

The third even integer is x+
4

Given that the sum of the first and the third is 131 less
than 3 times the second.

==> n + (n+4) = 3(n+2) -
131

Now we will combine
terms.

==> 2n + 4 = 3n + 6
-131

==> 4 - 6 + 131 =
n

==> n= 129

==>
n+2 = 131

==> n+4 =
133

Then the integers are 129, 131, and
133