What is (f o g)(36) if f(x)=6^x and g(x)=log6 x ?

According to the rule, (f o g)(x) =
f(g(x))

So,  (f o g)(36) =
f(g(36))

We'll calculate g(36) = log6 (36) = log6 (6^2) =
2*log6 (6) = 2

(f o g)(36) = f(g(36)) =
f(2)

We'll substitute x by 2 in the expression of
f(x):

f(2) = 6^2

f(2) =
36

The result of composition of the functions
is: (f o g)(36) = 36.