You need to write the factored form of the number 595 such
that:
`595 = 1*5*119`
Hence,
the divisors of 595 are `{1;5;119;595}`
You need to write
the factored form of the number 252 such that:
`252 =
1*2^2*3^2*7`
Hence, the divisors of 252 are
`{1;2;3;4;6;7;9;12;14;18;21;63;252}`
You need to notice
that the sets of divisors of 595 and 252 share in common only the number
1.
Hence, evaluating the greatest common
divisor of 252 and 595 yields that `G.C.D = 1`.
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