the graph of y=1/(x^2) between x=1 and x=2 is rotated about the y-axis. find the volume of the solid formed.

The solid formed by graph of y = 1/(x^2) between x=1 and
x=2 rotated about the y-axis, can be taken to be a series of cylinders of height dy and
a radius given by the value of x.

As y = 1/x^2, we first
write this as x^2 = 1/y or x = sqrt (1/y)

Also the limits x
= 1 and x = 2 are substituted with y = 1 and y = 1/4.

The
volume now is: Int [ pi* x^2 dy], y = 1 to y =
1/4

=> Int[ pi* (sqrt (1/y) )^2 dy] , y = 1 to y =
1/4

=> Int[ pi* (1/y) dy] , y = 1 to y =
1/4

=> Int[ pi* y^(-1) dy] , y = 1 to y =
1/4

=> (-1)*[ pi* y^-2] , y = 1 to y =
1/4

=> (-pi)*[ 1^-2 -
(1/4)^-2]

=> (-pi)*[ 1 -
16]

=> 
15*pi

The required volume of the solid is
15*pi.