Solve the system of equations 3x-2y=7 and 4x+2y=14?

We should use the elimination method because it's the
easiest. So first we have to identify the like terms. Which we can
see is
2y.

3x-2y=7

4x+2y=14

The
rule is that if the two terms are the same (-7x and -7x for example then we have to
subtract the equation) and if they're different (-2y and 2y for example) we have to add
the equation. Doing this we can eliminate
y.

Ok so the equation becomes
this

3x-2y=7

+ 
4x+2y=14     Now if we add it we
get:

7x=21 (the y's cancel
out because -2y + 2y is 0)

now to get x on it's own we have
to divide it by 7 because currently it's multiplying by it. We do this to both sides. So
it becomes:

x=21 divided by 7 (the 7's at the other side
cancel each other out)

so we're left with
x=3

Now we substitute x into the 1st equation (though u can
do it to any, it won't matter) which was
3x-2y=7

We
get

3 x
3-2y=7

9-2y=7 ( We want to get y on
it's own so we bring the 9 to the other side. Right now's it's positive, when we take it
to the other side it will become
negative)

-2y=7-9

-2y=-2
(Now we divide the -2 since it's multyplying. We do it to both sides) We
get:

y=-2 divided by -2 which
becomes

y=1

So the final
answer is x=3 and y=1

HOPE IT HELPED
:D